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A projectile of mass 0.5 kg is shot straight up with an initial speed of 18.8 m/s. How much energy is lost from the system if it reaches a max height of 15.9048 meters? 

1 Resposta

If no energy is lost, the energy at maximum height should be

mv2/2 = (0.5)(18.8)2/2J = 88.36 J

That should equal mghmax.

mghmax = (0.5)(9.8)(15.9048) J = 77.93 J

The energy lost is the difference between these two values.

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